# A rocket is in th

The diagram is given as:

For upper conical part,

Radius of base, r = 3 cm

Slant height, l = 5 cm

As,

l2 = h2 + r2, where h , r and l are height radius respectively.

h2 = l2 - r2

h2 = (5)2 - (3)2

h2= 25 - 9 = 16

h = 4 cm

Also,

volume of cone

Curved surface area of cone = πrl = π(3)(5) = 15π cm2

For cylindrical part,

Radius of base = Radius of base of conical part = r = 3 cm

Height, h = 12 cm

Also,

Volume of cylinder = πr2h = π(3)2(12) = 108π cm3

Curved surface area of cylinder = 2πrh = 2π(3)(12) = 72π cm2

Volume of rocket = volume of conical part + volume of cylindrical part

Volume of rocket = 12π + 108π = 120π

Also,

Surface area of rocket = Curved surface area of conical part + Curved surface area of Cylindrical part + Surface area of base of rocket

Surface area of base of rocket = πr2 = π(3)2 = 9π cm2

Therefore,

Surface area of rocket = 15π + 72π + 9π = 94π cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Sphere and Hemisphere16 mins
Right Circular Cylinder45 mins
Cube and Cuboid41 mins
Right Circular Cone And Frustum43 mins
Heights and Distances-I45 mins
History - Concept and Questions57 mins
Resources and Development Revision28 mins
Corrosion: Types, Pros and Cons41 mins
Revision on Substitution and Elimination Method44 mins
Area Related to Circles- Important Formula and Concepts59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses