Answer :

In a rhombus, all sides are equal.

Perimeter of rhombus = 40cm


Side of rhombus = 40/4 = 10cm


a = 10, b = 10, c = 12


s = (a + b + c)/2


s = (10 + 10 + 12)/2 = 32/2 = 16.


Area(ΔBCD) = √s(s-a)(s-b)(s-c)


Area(ΔBCD) = √16(16-10)(16-10)(16-12)


Area(ΔBCD) = √16×6×6×4


Area(ΔBCD) = 48 cm2


As ABCD is a rhombus, Area(ΔBCD) = Area(ΔABD)


Area of rhombus(ABCD) = Area(ΔBCD) + Area(ΔABD)


Area of rhombus(ABCD) = 48 + 48


Area of rhombus(ABCD) = 96cm2


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