Q. 74.5( 8 Votes )

# The perimeter of

Given that the sides are in ratio of 6:7:8

Let the sides of the triangle be 6x, 7x and 8x.

Perimeter(Δ) = 420

6x + 7x + 8x = 420

21x = 420

x = 20

Therefore the sides are 120m, 140m and 160m.

a = 120, b = 140, c = 160

s = (a + b + c)/2

s = (120 + 140 + 160)/2 = 420/2 = 210.

Area(Δ) = √s(s-a)(s-b)(s-c)

Area(Δ) = √210(210-120)(210-140)(210-160)

Area(Δ) = √210×90×70×50

Area(Δ) = 2100√15 m2

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