Q. 54.4( 23 Votes )

# In the adjacent figure, AB is a chord of circle with centre O. CD is the diameter perpendicualr to AB. Show that AD = BD.

Answer :

Given, AB is a chord of circle with centre O. CD is the diameter

perpendicular to AB.

We know that line drawn from the center of a circle to the chord

Perpendicular to it bisects the chord.

AP = BP

In ADP and BDP,

AP = BP

APD = BPD = 90

PD = PD (Common)

ADP BDP

AD = BD (CPCT)

Rate this question :

In the figure, if AB = CD and ∠AOB = 90° find ∠COD

AP- Mathematics

In the figure, ‘O’ is the centre of the circle. OM = 3cm and AB = 8cm. Find the radius of the circle

AP- Mathematics

In the figure, PQ = RS and ∠ORS = 48°. Find ∠OPQ and ∠ROS.

AP- Mathematics

In the given figure ‘O’ is the centre of the circle and AB, CD are equal chords. If ∠AOB = 70°. Find the angles of the ∆OCD.

AP- Mathematics

In the adjacent figure, AB is a chord of circle with centre O. CD is the diameter perpendicualr to AB. Show that AD = BD.

AP- Mathematics

In the figure, ∠BAD = 40° then find ∠BCD.

AP- Mathematics