Q. 4 E3.7( 6 Votes )

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Answer :

In the given term


Dividend = 15lm (2p2–2q2)


In given expression (2p2–2q2)


Take out the common factor in binomial term


(2 × p × p – 2 × q × q)


2(p2 – q2)


Both terms are perfect square


p2 = p × p


q2 = q × q


(p2 – q2) Seems to be in identity a2-b2 = (a + b)(a-b)


Where a = p and b = q;


p2 – q2 = (p + q)(p – q)


Hence the factors of p2 – q2 are (p + q) and (p – q)


Divisor = 3l (p + q)


=


=


= 10m(p – q)


Hence dividing 15lm (2p2–2q2) by 3l (p + q) gives out 10m(p – q)


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