# Using section for

Let the point P divides AB in the ratio k : 1.

Then,

Comparing this information with the details given in the question, we have

x1 = 2, y1 = -3, z1 = 4; x2 = -1, y2 = 2, z2 = 1 and m = k, n = 1

By section formula,

We know that the coordinates of the point R which divides the line segment joining two points P (x1, y1, z1) and Q (x2, y2, z2) internally in the ratio m : n is given by: So, we have,

The coordinates of P = Now, we check if for some value of k, the point coincides with the point C.

Put -k + 2 = 0 k = 2

When k =2, then And Therefore, C is a point which divides AB in the ratio 2 : 1 and is same as P.

Hence, A, B, C are collinear.

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