Q. 3 C4.3( 10 Votes )

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Answer :

In the given term


Dividend = 11a3b3(7c – 35) ÷ 3a2b2(c – 5)


Take out the common part in binomial term


= 11 × a × a × a × b × b × b (7 × c - 5 × 7 )


= 11 × a × a × a × b × b × b × 7 (c - 5 )


= 77a3b3(c - 5)


Divisor = 3a2b2(c – 5)


=


= ab


Hence dividing 11a3b3(7c – 35) by 3a2b2(c – 5) gives out ab


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