Answer :
In the given term
Dividend = (
a2b2c2 + 
ab2c2)
Take out the common part in binomial term
= (
× a × a × b × b × c × c + 
× 2 × a × b × b × c × c )
= 
× a × b × b × c × c (a + 2)
= 
ab �2c2(a + 2)
Divisor = 
abc
= 
= 
= 
bc(a + 2)
Hence dividing (
a2b2c2 + 
ab2c2) by 
abc gives out 
bc(a + 2)
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