Q. 2 G3.7( 19 Votes )

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Answer :

In the given term


Dividend = ( a2b2c2 + ab2c2)


Take out the common part in binomial term


= ( × a × a × b × b × c × c + × 2 × a × b × b × c × c )


= × a × b × b × c × c (a + 2)


= ab 2c2(a + 2)


Divisor = abc


=


=


= bc(a + 2)


Hence dividing ( a2b2c2 + ab2c2) by abc gives out bc(a + 2)


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