Answer :

Let ABCD is a trapezium in which AB = 77 cm, BC = 26 cm, CD = 60 cm, DA = 25 cm

Draw CE// AD

Now, ACDE is a parallelograme

BE = AB-DC = 77-60 = 17 cm

In ∆BEC, Let a, b and c are the sides of triangle and

And s be the semi-perimeter, then its area

A = where

= = 34

A=

A = = m^{2}

Therefore area of ∆BCE =

204 × 2 = 17× Altitude

Altitude = 24 cm

Area of trapezium ABCD = =

⇒

Therefore area of trapezium ABCD = 1644 cm^{2}

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