Q. 4 E4.6( 5 Votes )

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Answer :

In the given expression


1st and last terms are perfect square


x4 = x2 × x2


y4 = y2 × y2


And the middle expression is in form of 2ab


2x2y2 = 2 × x2 × y2


x2 × x2 - 2 × x2 × y2 + y2 × y2


Gives (a-b)2 = a2-2ab + b2


x4 – 2x2y2 + y4


a = x2 and b = y2;


x4 – 2x2y2 + y4 = (x2 – y2) (x2 + y2)


Hence the factors of x4 – 2x2y2 + y4 are (x2 – y2) and (x2 + y2)


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