Q. 4 A4.0( 4 Votes )

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Answer :

In expression x4 – y4


Both terms are perfect square


x4 = x2 × x2


y4 = y2 × y2


x4 – y4 Seems to be in identity a2-b2 = (a + b)(a-b)


Where a = x2 and b = y2;


x4 – y4 = (x2 – y2)( x2 + y2),


x2 – y2 Seems to be in identity a2-b2 = (a + b)(a-b)


Where a = x and b = y;


x2 – y2 = (x– y)( x+ y),


x4 – y4 = (x– y)( x+ y), ( x2 + y2)


Hence the factors of x4 – y4 are (x– y),( x+ y) and ( x2 + y2)


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