Q. 44.1( 390 Votes )

A chord of a circ

Answer :


Let AB be the chord of the circle subtending 90° angle at centre O of the circle.



= 3.14 × 25
= 78.5 cm2

OAB is a right angles triangle, 
Area of triangle OAB = 1/2 (base x height)
Area of ΔOAB = x OA x OB


=  x 10 x 10


= 50 cm2


Area of minor segment ACB = Area of minor sector OACB -Area of ΔOAB


= 78.5 - 50


= 28.5 cm2
ii) Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OACB =
 

=3/4 x 3.14 x 10 x 10

=235.5cm2

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