Q. 44.2( 342 Votes )

A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:
(i) Minor segment

(ii) Major sector (Use π = 3.14)

Answer :


Let AB be the chord of the circle subtending 90° angle at centre O of the circle.



= 3.14 × 25
= 78.5 cm2

OAB is a right angles triangle, 
Area of triangle OAB = 1/2 (base x height)
Area of ΔOAB = x OA x OB


=  x 10 x 10


= 50 cm2


Area of minor segment ACB = Area of minor sector OACB -Area of ΔOAB


= 78.5 - 50


= 28.5 cm2
ii) Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OACB =
 

=3/4 x 3.14 x 10 x 10

=235.5cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Area Related with Circles47 mins
Quiz | Imp. Qs. on Circles37 mins
Quiz | Testing Your Knowledge on Circles32 mins
Short Cut Trick to Find Area of Triangle43 mins
Champ Quiz | Area Related with the Circle45 mins
Tricks to MemoriseFREE Class
Smart and Effective study is the Key of success45 mins
An Introduction to pH?30 mins
Various Tricks for How to Study Effectively32 mins
How to solve puzzles?36 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses