# A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding:(i) Minor segment(ii) Major sector (Use π = 3.14)

Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

= 3.14 × 25
= 78.5 cm2

OAB is a right angles triangle,
Area of triangle OAB = 1/2 (base x height)
Area of ΔOAB = x OA x OB

=  x 10 x 10

= 50 cm2

Area of minor segment ACB = Area of minor sector OACB -Area of ΔOAB

= 78.5 - 50

= 28.5 cm2
ii) Let AB be the chord of the circle subtending 90° angle at centre O of the circle.

Area of major sector OACB =

=3/4 x 3.14 x 10 x 10

=235.5cm2

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