The sides of a qu

Let consider a quadrilateral ABCD

In ∆ABC;

AC = = 13 m

AB = a = 5 m, BC = b = 12 m, AC = c = 13 m

Let a, b and c are the sides of triangle and s is

the semi-perimeter, then its area is given by:

A = where [Heron’s Formula]

= = 15

A₁ =

A₁ = = m²

In ∆ADC;

DA = a = 15 m, CD = b = 14 m, AC = c = 13 m

Let a, b and c are the sides of triangle and s is

the semi-perimeter, then its area is given by:

A = where

= = 21

A₂ =

A₂ = = m²

Therefore area of quadrilateral ABCD = A₁ + A₂ = 30+84 = 114 m²