Q. 2 F4.6( 8 Votes )

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Answer :

In given expression


Take out the common factor,


[2 × 3 × x × x-2 × 3 × 3 × 3]


2 × 3[x × x-3 × 3]


6[x2-9]


Both terms are perfect square


x2 = x × x


9 = 3 × 3


x2– 9 Seems to be in identity a2-b2 = (a + b)(a-b)


Where a = x and b = 3;


x2– 9 = (x-3)(x + 3)


Hence the factors of 6x2 – 54 are 6,(x-3) and (x + 3)


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