Answer :
In given expression
Both terms are perfect square
⇒ m2 = m × m
⇒ 121 = 11 × 11
∴ m2-121 Seems to be in identity a2-b2 = (a + b)(a-b)
Where a = m and b = 11;
m2 – 121 = (m + 11)(m-11)
Hence the factors of m2 – 121 are (m + 11) and (m-11)
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