Answer :
In given expression
Both terms are perfect square
⇒ x2 = x × x
⇒ 36 = 6 × 6
∴ x2-62
Seems to be in identity a2-b2 = (a + b)(a-b)
Where a = x and b = 6;
x2 – 36 = (x + 6)(x-6)
Hence the factors of x2 – 36 are (x + 6) and (x-6)
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