# The sides of a qu

AC = = 25 cm

In ∆ABC

AB = a = 26 cm, BC = b = 27 cm, AC = c = 25 cm

Let a, b and c are the sides of triangle and s is

the semi-perimeter, then its area is given by:

A = where

= = 39

A1 =

A1 = = cm2

DA = a = 24 cm, CD = b = 7cm, AC = c = 25 cm

Let a, b and c are the sides of triangle and s is

the semi-perimeter, then its area is given by:

A = where [Heron’s Formula]

= = 28

A2 =

A2 = = cm2

Therefore area of quadrilateral ABCD = A1 + A2 = 291.85+84 = 375.85 cm2

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