Q. 1 F5.0( 3 Votes )

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Answer :

In the given expression

1st and last terms are perfect square

81x2 = 9x × 9x

121y2 = 11y × 11y

And the middle expression is in form of 2ab

198xy = 2 × 9x × 11y

9x × 9x - 2 × 11y × 9x + 11y × 11y

Gives (a-b)2 = a2-2ab + b2

In 81x2 – 198xy + 121y2

a = 9x and b = 11y;

81x2 – 198xy + 121y2 = (9x-11y)2

Hence the factors of 81x2 – 198xy + 121y2 are (9x-11y)and (9x-11y)

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