Q. 1 F5.0( 3 Votes )

Factories the following expression-

81x2– 198 xy + 121y2

Answer :

In the given expression


1st and last terms are perfect square


81x2 = 9x × 9x


121y2 = 11y × 11y


And the middle expression is in form of 2ab


198xy = 2 × 9x × 11y


9x × 9x - 2 × 11y × 9x + 11y × 11y


Gives (a-b)2 = a2-2ab + b2


In 81x2 – 198xy + 121y2


a = 9x and b = 11y;


81x2 – 198xy + 121y2 = (9x-11y)2


Hence the factors of 81x2 – 198xy + 121y2 are (9x-11y)and (9x-11y)


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