Q. 1 D4.3( 15 Votes )

# Find the distance

Let P be (2, – 1, 3) and Q be (– 2, 1, 3)

Distance PQ Here,

x1 = 2, y1 = – 1, z1 = 3

x2 = – 2, y2 = 1, z2 = 3

Distance PQ     Thus, the required distance is units.

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