Answer :

Let P(n):


For n =1 is true,


P(1):


=


Since, P(n) is true for n =1


Now, For n = k


P(k): - - - - (1)


We have to show that,



Now,



= using equation (1)


=


Therefore, P(n) is true for n = k + 1


Hence, P(n) is true for all n ϵ N by PMI


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