Q. 95.0( 9 Votes )

# The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9 paise per cm^{2} is

A. Rs 2.00

B. Rs 2.16

C. Rs 2.48

D. Rs 3.00

Answer :

a = 6, b = 8, c = 10

s = (a + b + c)/2

⇒ s = (6 + 8 + 10)/2 = 24/2 = 12.

Area(Δ) = √s(s-a)(s-b)(s-c)

⇒ Area(Δ) = √12(12-6)(12-8)(12-10)

⇒ Area(Δ) = √12×6×4×2

⇒ Area(Δ) = 24cm^{2}

Cost of painting = Area(Δ)×Cost per cm^{2}

⇒ Cost of painting = 24×9 = 216 paise = Rs 2.16

Hence, the correct option is (B).

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