# Minimize Z = x +

It is given in the question that,

Z = x + 2y

We have to subject on the following equation:

(x, y) = (0, 3), (6, 0)

(x, y) = (0, 3), (1, 1)

As per the table minimum value of Z is 6 but we can see that the feasible region is unbounded. Thus, 6 may or may not be the minimum value of Z

We will plot the graph of inequality,

Here we will see that there is no common point with the feasible region.

Hence, Z will be minimum on all points joining line (0, 3), (6, 0). Therefore, Z will be minimum on x + 2y = 6

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