# If y = x3</s

Basic idea:

√Second order derivative is nothing but derivative of derivative i.e. √The idea of chain rule of differentiation: If f is any real-valued function which is the composition of two functions u and v, i.e. f = v(u(x)). For the sake of simplicity just assume t = u(x)

Then f = v(t). By chain rule, we can write the derivative of f w.r.t to x as: √Product rule of differentiation- √Apart from these remember the derivatives of some important functions like exponential, logarithmic, trigonometric etc..

Let’s solve now:

As we have to prove : We notice a third order derivative in the expression to be proved so first take the step to find the third order derivative.

Given, y = x3 log x

Let’s find - As So lets first find dy/dx and differentiate it again. differentiating using product rule:  [ log x) = ] Again differentiating using product rule:  [ log x) = ] Again differentiating using product rule:  [ log x) = ] Again differentiating w.r.t x : Rate this question :

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