Answer :

**Given:** The sides of the triangle are 15 m, 11 m and 6 m.**To find:** Area painted in color**Explanation:**

**Perimeter of the triangular walls = sum of 3 sides **

Perimeter = 15 + 11 + 6 = 32 m

Semi perimeter of triangular walls(s) =

= 16 m

Using Heron’s formula,

Area of the advertisement = Area of triangle =

where, s = semi perimeter of the triangle

a, b and c are the sides of the triangle

Therefore for the given triangle,

Area =

=

=

= √800 m^{2}

= √(20 × 20 × 2)

(Taking 20 outside the square root, as a pair is present in square root, we get,)

**Thus the area of painted color is 20√2 m ^{2}.**

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