Q. 34.3( 39 Votes )

Maximise Z = 5x + 3y subject to 3x + 5y ≤ 15, 5x + 2y ≤ 10, x ≥ 0, y ≥ 0.

Answer :

It is given in the question that,

Z = 5x + 3y


We have to subject on the following equation:


3x +5y ≤ 15, 5x+2y ≤ 10, x ≥ 0, y ≤ 0


5x+2y ≤ 10



(x, y) = (0, 5), (2, 0)




(x, y) = (0, 3), (5, 0)




We can clearly see that Z is maximum at . Hence, maximum value of Z will be


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