Q. 24.4( 43 Votes )

Minimise Z = – 3x + 4 y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.

Answer :

It is given in the question that,

Z = - 3x + 4y


We have to subject on the following equation:


x +2y ≤ 8, 3x+2y ≤ 12, x ≥ 0, y ≤ 0


3x+2y ≤ 12



(x, y) = (0, 6), (4, 0)


x+2y ≤ 8



(x, y) = (0, 4), (8, 0)




We can clearly see that Z is minimum at (4, 0). Hence, minimum value of Z will be - 12


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