Q. 135.0( 3 Votes )

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is
A. 4950 cm2

B. 4951 cm2

C. 4952 cm2

D. 4953 cm2

Answer :

Clearly, the given bucket is in the form of frustum of a cone.

And we know

Curved surface area of frustum of a cone = πl(r1 + r2)

Where, l = slant height,

r1 and r2 are radii (r1 > r2)

For given bucket,

Radius of top, r1 = 28 cm

Radius of bottom, r2 = 7 cm

Slant height, l = 45 cm


Curved surface area of bucket = π(45)(28 + 7)

= 4950 cm2

So, the curved surface area of bucket is 4950 cm2.

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