Q. 724.5( 10 Votes )
Ajita starts off from home at 07.00 hours with her father on a scooter that goes at a uniform speed of 30km/h and drops her at her school after half an hour. She stays in the school till 13 30hours and takes an auto rickshaw to return home. The rickshaw has a uniform speed of 10km/h. Draw the graph for the above situation and also determine the distance of Ajita’s school from her house.
Answer :
Given that, Ajita goes to school at a uniform speed on her father’s scooter = 30km/h
Time taken to reach her school = 30 min = 
Distance between her home and school = speed × time taken to reach
= 
= 15 km
∴ Distance = 15 KM
∴ Distance covered by Ajita in 1 min = 1/2 km = 500m
The graph of the above situation is as follows
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