# Two parallel side

The figure is given below: According to the question,

AB = 14 cm DC = 6cm. Also AD = BC = 5 cm

( trapezium is isosceles)

Also, DC = EF can be seen from the figure.

Also AE = FB = x

So we can say

AE + EF + FB = AB

x + 6 + x = 14

2x = 8

x = 4.

AE = FB = 4.

Now in ΔAED,

AED = 90°

By pythogares theorem

We get

(5)2 = (4)2 + (ED)2

(ED)2 = 25–16 = 9

ED = 3

Hence distance between two parallel sides is 3 cm.

Area of the trapezium is given by

= ×(sum of parallel sides)×(distance between them)

= = = 30cm2

The area of a trapezium is 30cm2.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Heron's Formula- Full Gyan46 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

In Q. No. 1, if ARD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a paralleRD Sharma - Mathematics

In Δ ABC, ERD Sharma - Mathematics

P is the mid-poinRD Sharma - Mathematics

Diagonals of a quRD Sharma - Mathematics

ABCD is a trapeziRD Sharma - Mathematics