Q. 53.6( 8 Votes )

Two parallel side

Answer :

The figure is given below:



According to the question,


AB = 14 cm DC = 6cm. Also AD = BC = 5 cm


( trapezium is isosceles)


Also, DC = EF can be seen from the figure.


Also AE = FB = x


So we can say


AE + EF + FB = AB


x + 6 + x = 14


2x = 8


x = 4.


AE = FB = 4.


Now in ΔAED,


AED = 90°


By pythogares theorem


We get


(AD)2 = (AE)2 + (ED)2


(5)2 = (4)2 + (ED)2


(ED)2 = 25–16 = 9


ED = 3


Hence distance between two parallel sides is 3 cm.


Area of the trapezium is given by


= ×(sum of parallel sides)×(distance between them)


=


=


= 30cm2


The area of a trapezium is 30cm2.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Heron's Formula- Full GyanHeron's Formula- Full GyanHeron's Formula- Full Gyan46 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

In Q. No. 1, if ARD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a paralleRD Sharma - Mathematics

In Δ ABC, ERD Sharma - Mathematics

P is the mid-poinRD Sharma - Mathematics

Diagonals of a quRD Sharma - Mathematics

ABCD is a trapeziRD Sharma - Mathematics