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# Refer to Exercise 32, Maximum of F – Minimum of F =

A. 60

B. 48

C. 42

D. 18

Correct

Answer :

F = 4x + 6y

Corner points - (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5).

Value of F at corner points –

At (0, 2), F = 12

At (3, 0), F = 12

At (6, 0), F = 24

At (6, 8), F = 72

At (0, 5), F = 30

Feasible region –

Considering, feasible region to be bounded so it is a closed polygon.

Minimum value of F = 12

Maximum value of F = 72

So, Maximum of F – Minimum of F = 60.

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PREVIOUSCorner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5).Let F = 4x + 6y be the objective function.The Minimum value of F occurs atNEXTCorner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px+qy, where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is

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