Answer :

It is given that f : R R given by f (x) = x2

We can see that f(-1) = f(1) = 1, but -1 ≠ 1


f is not injective.


Now, let -2 ϵ R. But, we can see that there does not exists any x in R such that


f(x) = x2 = -2


f is not surjective.


Therefore, function f is neither injective nor surjective.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Fill in theMathematics - Exemplar

State True Mathematics - Exemplar

State True Mathematics - Exemplar

State True Mathematics - Exemplar

Let A = {1, 2, 3}Mathematics - Exemplar

Show that the relMathematics - Board Papers

Let N denote the Mathematics - Board Papers