Q. 185.0( 1 Vote )

# Show that the thr

Given; Three points A (2, 3, 4), B (–1, 2, – 3) and C (– 4, 1, – 10)  =√59  =√59  =√236

=2√59

AB + BC = AC; Points A, B and C are collinear.

AC: BC = 2√59:√59 = 2:1

from the lengths of AB, BC and AC we can say that C divides AB in the ratio 2:1 externally.

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