Answer :
Let the firm has x number of large vans and y number of small vans. We make the following table from the given data:
Thus according to the table, the cost becomes, Z=400x+200y
Now, we have to minimize the cost, i.e., minimize Z=400x+200y
The constraints so obtained, i.e., subject to the constraints,
200x+80y≥ 1200
Now will divide throughout by 40, we get
⇒ 5x+2y≥ 30…………..(i)
And 400x+200y≤3000
Now will divide throughout by 200, we get
⇒ 2x+y≤ 15…………..(ii)
Also given the number of large vans cannot exceed the number of small vans
⇒ x≤ y……………..(iii)
And x≥0, y≥0 [non-negative constraint]
So, minimize cost we have to minimize Z=400x+200y subject to
5x+2y≥ 30
2x+y≤ 15
x≤ y
x≥0, y≥0
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