Answer :

Given:


Z=x + 2y


From the given figure, the shaded region PRQS is the feasible region is bounded, so maximum and minimum value will occur at a corner point of the feasible region.


Corner Points are


Now we will substitute these values in Z at each of these corner points, we get



Hence, the maximum value of Z is 9 at the point .


And the minimum value of Z is at the point .


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