Q. 23.8( 25 Votes )
In a square PQRS, diagonals bisect each other at O. Prove that ΔPOQ ≅ ΔQOR ≅ ΔROS ≅ ΔSOP.
Answer :
In ΔPOQ, ΔQOR , ΔROS, and ΔSOP
PQ = QR = RS = SP (All sides of a square are equal)
∠POQ = ∠QOR = ∠ROS = ∠SOP = 900 (Diagonals of a square bisect at right angle)
PO = QO = RO = SO (Diagonals bisect each other)
So ΔPOQ ≅ ΔQOR ≅ ΔROS ≅ ΔSOP by S.A.S. axiom of congruency
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