Q. 23.8( 25 Votes )

In a square PQRS, diagonals bisect each other at O. Prove that ΔPOQ ΔQOR ΔROS ΔSOP.

Answer :

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In ΔPOQ, ΔQOR , ΔROS, and ΔSOP


PQ = QR = RS = SP (All sides of a square are equal)


POQ = QOR = ROS = SOP = 900 (Diagonals of a square bisect at right angle)


PO = QO = RO = SO (Diagonals bisect each other)


So ΔPOQ ΔQOR ΔROS ΔSOP by S.A.S. axiom of congruency


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