Answer :

AB = 18 cm, DC = 32 cm


Distance between AB and DC = Height = 14 cm


Now, Area of the trapezium = (1/2) × (Sum of parallel sides) × Height


= (1/2) × (18+32) × 14 = 350cm2


As AB DC, A + D = 180°


and B + C = 180°


Also, radius of each arc = 7 cm


Therefore,


Area of the sector with central angle A = (1/2) × (A/180) × π × r2


Area of the sector with central angle D = (1/2) × (D/180) × π × r2


Area of the sector with central angle B (1/2) × (B/180) × π × r2


Area of the sector with central angle C = (1/2) × (C/180) × π × r2


Total area of the sectors =




= 77 + 77 = 154


Area of shaded region = Area of trapezium – (Total area of sectors)


= 350 – 154 = 196 cm2


Hence, the required area of shaded region is 196 cm2.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigo Marathon Part 2Trigo Marathon Part 2Trigo Marathon Part 245 mins
Trigo Marathon Part 1Trigo Marathon Part 1Trigo Marathon Part 146 mins
Application of Trigo Important QuestionsApplication of Trigo Important QuestionsApplication of Trigo Important Questions44 mins
How to Revise ChemistryHow to Revise ChemistryHow to Revise Chemistry45 mins
Nelson Mandela : Long Walk to FreedomNelson Mandela : Long Walk to FreedomNelson Mandela : Long Walk to Freedom42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the area of RS Aggarwal - Mathematics