Draw a line AX and with A as center and radius 6cm cut an arc on AX at C.
Construct perpendicular bisector of AC and name it as PQ.
Name the intersecting point O.
With O as the center and radius 2cm draw arcs to cut OP and OQ at D and B respectively.
Join AB,BC,CD and DA.
AC=6cm (By Construction)
PQ is perpendicular to AC (By Construction)
As AC=6cm is one the diagonals So BD is the other diagonal with length 4cm.
As it is a rhombus we know that the diagonals bisect each other so
Thus our construction is justified.
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