Answer :

Sides of the triangle are 15 m, 16 m, and 17 m.

Now, perimeter of the triangle = (15+16+17) m = 48 m

∴ Semi-perimeter of the triangle = s = 48/2 = 24 m

By Heron’s formula, Area of the triangle =

(where a, b, c are the sides of triangle)

=

= 109.982 m^{2}

Let B, C and H be the corners of the triangle on which buffalo, cow and horse are tied respectively with ropes of

7 m each.

So, the area grazed by each animal will be in the form of a sector.

∴ Radius of each sector = r = 7 m

Let x, y, z be the angles at corners B, C, H respectively.

∴ Area of sector with central angle x =

Area of sector with central angle y =

Area of sector with central angle z =

Area of field not grazed by the animals = Area of triangle – (area of the three sectors)

=

=

= 109.892 – 77 = 32.982 cm^{2}

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Find the area of RS Aggarwal - Mathematics