Answer :

Sides of the triangle are 15 m, 16 m, and 17 m.


Now, perimeter of the triangle = (15+16+17) m = 48 m


Semi-perimeter of the triangle = s = 48/2 = 24 m


By Heron’s formula, Area of the triangle =


(where a, b, c are the sides of triangle)


=


= 109.982 m2



Let B, C and H be the corners of the triangle on which buffalo, cow and horse are tied respectively with ropes of


7 m each.


So, the area grazed by each animal will be in the form of a sector.


Radius of each sector = r = 7 m


Let x, y, z be the angles at corners B, C, H respectively.


Area of sector with central angle x =



Area of sector with central angle y =



Area of sector with central angle z =



Area of field not grazed by the animals = Area of triangle – (area of the three sectors)


=


=


= 109.892 – 77 = 32.982 cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigo Marathon Part 2Trigo Marathon Part 2Trigo Marathon Part 245 mins
Application of Trigo Important QuestionsApplication of Trigo Important QuestionsApplication of Trigo Important Questions44 mins
Trigo Marathon Part 1Trigo Marathon Part 1Trigo Marathon Part 146 mins
How to Revise ChemistryHow to Revise ChemistryHow to Revise Chemistry45 mins
Nelson Mandela : Long Walk to FreedomNelson Mandela : Long Walk to FreedomNelson Mandela : Long Walk to Freedom42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the area of RS Aggarwal - Mathematics