Sides of the triangle are 15 m, 16 m, and 17 m.
Now, perimeter of the triangle = (15+16+17) m = 48 m
∴ Semi-perimeter of the triangle = s = 48/2 = 24 m
By Heron’s formula, Area of the triangle =
(where a, b, c are the sides of triangle)
= 109.982 m2
Let B, C and H be the corners of the triangle on which buffalo, cow and horse are tied respectively with ropes of
7 m each.
So, the area grazed by each animal will be in the form of a sector.
∴ Radius of each sector = r = 7 m
Let x, y, z be the angles at corners B, C, H respectively.
∴ Area of sector with central angle x =
Area of sector with central angle y =
Area of sector with central angle z =
Area of field not grazed by the animals = Area of triangle – (area of the three sectors)
= 109.892 – 77 = 32.982 cm2
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Find the area ofRS Aggarwal - Mathematics