Draw ∠YBX = 90°.
With B as center and radius 3.5cm and 5.5cm respectively cut arcs intersecting BX at C and BY at Z.
Join ZC and construct its perpendicular bisector intersecting BY at A.
ABC is the required triangle.
Here ∠ABC=90° , BC=3.5cm by construction.
As A is the point of intersection of the perpendicular bisector and CZ,
So, AZ=AC which means AB+AZ=5.5cm
And at the same time AB+AC=5.5cm
Hence the triangle Construction is justified.
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