Answer :

Step 1:

Draw a line QR=3cm.

Step 2:

Construct an angle of 45° at Q.

Step 3:

With Q as center and 2cm as radius cut an arc on QX at S.

Step 4:

Join SR and bisect it.

Name the intersecting point of QX and the bisector P.

Step 5:

Join PR.

PQR is the required Triangle.

__Justification__

QR and ∠PQR =45°.

P lies on the perpendicular bisector of SR.

PS = PR

Given,

QS = PQ – PS

= PQ -PR (as PS=PR)

Thus The construction is justified.

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