Given: (ax2 + by2) (ax2 + by2),it is a product of 2 binomial expressions which have the same terms ax2 + by2 and ax2 + by2.
Now when we compare these expressions with the identities, we
find it in the form of (a + b)2,where a = ax2 and b = by2,
The identity (a + b)2 = a2 + 2ab + b2,
Hence, (ax2 + by2) (ax2 + by2) = (ax2 + by2)2 = (ax2)2 + 2(ax2)(by2) + (by2)2
= a2x4 + 2abx2y2 + b2y4
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