Given: (3k + 4l) (3k + 4l),it is a product of 2 binomial expressions which have the same terms 3k + 4l and 3k + 4l.
Now when we compare these expressions with the identities, we
find it in the form of (a + b)2,where a = 3k and b = 4l,
The identity (a + b)2 = a2 + 2ab + b2,
Hence, (3k + 4l) (3k + 4l) = (3k + 4l)2 = (3k)2 + 2(3k)(4l) + (4l)2 = 9k2 + 24kl + 16l2
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