Q. 54.3( 213 Votes )

# Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m2 of area is painted. How many cans of paint will she need to paint the room?

Let length, breadth and height of room be l, b and h respectively
Given,
l = 15 m
b = 10 m
h = 7 m

and we know, area of four walls = 2(l + b)h

Hence,

Area to be painted = Area of four Walls of a Room + area of ceiling
= 2(l + b)h + lb
= 2(15 + 10)7 + 15(10)
= 14(25) + 150
= 350 + 150
= 500 m2

As, one can of paint is enough for 100 sq m

So, 500/100 = 5 cans are needed to paint the hall.

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