Draw ∠YBX = 60° and BC=5cm
With B as center and 7.5cm as radius draw an arc that intersects BY at Z.
Join CZ and then with C as center draw two arc at either side of the line CZ and repeat the same with Z as center.
Name the intersecting points as P and Q.
Name the intersecting point of PR and BZ as A and join AC.
So ABC is the required Triangle and here we can observe that AZ=AC (as AZC is isosceles).
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