Answer :

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Δ ABC is an equilateral triangle


CD is drawn such that CD = BC


ACB = 600(Interior angle of an equilateral triangle)


ACD = 1800-600 = 1200(Angle on a straight line)


In an equilateral triangle since all sides are equal so


AC = CD


Hence Δ ACD is isosceles


Since base angles of an isosceles triangle is equal so


CAD = CDA = x(Let us assume)


ACD + CAD + CDA = 1800(Sum of interior angles of a triangle)


2x = 1800-1200 = 600


x = 300


ADC = 300


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