Q. 44.0( 24 Votes )

# Suppose ABC is an

Answer : Δ ABC is an equilateral triangle

CD is drawn such that CD = BC

ACB = 600(Interior angle of an equilateral triangle)

ACD = 1800-600 = 1200(Angle on a straight line)

In an equilateral triangle since all sides are equal so

AC = CD

Hence Δ ACD is isosceles

Since base angles of an isosceles triangle is equal so

CAD = CDA = x(Let us assume)

ACD + CAD + CDA = 1800(Sum of interior angles of a triangle)

2x = 1800-1200 = 600

x = 300

ADC = 300

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