Q. 3 A4.4( 20 Votes )

# In each of the fo

Answer :

Δ ABC is isosceles with AB = AC

∠BAC = 40^{0}(Given)

In an isosceles triangle since the base angles are equal so

∠ABC = ∠ACB = y (Let’s assume)

∠ABC + ∠ACB + ∠BAC = 180^{0}(Sum of interior angles of a triangle)

⇒ 2y = 180^{0}-40^{0} = 140^{0}

⇒ y = 70^{0}

⇒ ∠ACB = 70^{0}

∠ACB + x = 180^{0}(Angle on a straight line)

⇒ x = 180^{0} - 70^{0} = 110^{0}

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