Answer :

The eq. of the given planes are

2x – y + 3z – 1 = 0 and 2x – y + 3z + 3 = 0


Two planes are if the direction ratio of the normal to the plane is


a1a2 + b1b2 + c1c2 = 0


2 × 2 + (-1) × (-1) + 3 × 3


14 ≠ 0


Both the planes are not to each other.


Two planes are || to each other if the direction ratio of the normal to the plane is





Thus, the given planes are || to each other.


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