Answer :

The eq. of the given planes are

2x + y + 3z – 2 = 0 and x – 2y + 5 = 0


Two planes are if the direction ratio of the normal to the plane is


a1a2 + b1b2 + c1c2 = 0


2 × 1 + 1 × (-2) + 3 × 0


= 0


Thus, the given planes are to each other.


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