# Find the area of the minor segment of a circle of radius 14 cm, when the angle of the corresponding sector is 60°. Let r be the radius of the circle = 14 cm

Angle subtended at the center of the sector = θ = 60°

In triangle AOB, AOB = 60°, OAB = OBA = θ

Since, sum of all interior angles of a triangle is 180°

θ + θ + 60 = 180

2 θ = 120

θ = 60

Each angle is of 60° and hence the triangle AOB is an equilateral triangle.

Now, Area of the minor segment = Area of the sector AOBC – Area of triangle AOB

Angle subtended at the center of the sector = 60°

Angle subtended at the center (in radians) = θ = 60π/100 = π/3

Area of a sector of a circle = r2θ/2

= = 308/3 cm2

Area of the equilateral triangle =   Area of minor segment = = 17.796 cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Quiz | Area Related with Circles47 mins  Champ Quiz | Area Related with the Circle45 mins  Quiz | Imp. Qs. on Circles37 mins  Short Cut Trick to Find Area of Triangle43 mins  Surface Area and Volume49 mins  Surface Area and Volumes43 mins  Quiz | Surface Area and Volumes42 mins  Smart and Effective study is the Key of success45 mins  Tricks to MemoriseFREE Class  Various Tricks for How to Study Effectively32 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 