<span lang="EN-US

Here we have 3k(5k−l + 3m) and 6k(2k + 3l−2m)

Using the distributive law 3k(5k−l + 3m) = 15k²-3kl + 9km

and 6k(2k + 3l-2m) = 12k² + 18kl-12km

Now , we have to subtract 15k²-3kl + 9km from 12k² + 18kl-12km.

i.e. (12k² + 18kl-12km)-(15k²-3kl + 9km) = -3k² + 21kl-21k²m²

Hence after subtraction of the product of 3k(5k−l + 3m) from the product of 6k(2k + 3l−2m) is = -3k² + 21kl-21k²m²